CBSE Class 11-science Answered
Bond order of N2 is greater than N2+ but of O2 is less than that of O2+.Explain.
Asked by jgjaigupta1998 | 23 Aug, 2014, 04:14: PM
Expert Answer
In case of nitrogen, N2 → N2+ + e-
Electron is lost from bonding MO and the bond order decreases from 3 to 2.5.As a result, bond dissociation energy decreases and the bond length increases.
In case of oxygen, O2 → O2+ + e-
Electron is lost from antibonding MO and the bond order increases from 2 to 2.5. As a result, bond dissociation energy increases but bond length decreases.
Answered by Vaibhav Chavan | 25 Aug, 2014, 11:01: AM
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