Bond order of N2 is greater than N2+ but of O2 is less than that of O2+.Explain. 

 

Asked by jgjaigupta1998 | 23rd Aug, 2014, 04:14: PM

Expert Answer:

In case of nitrogen, N2  → N2+   +  e-

Electron is lost from bonding MO and the bond order decreases from 3 to 2.5.As a result, bond dissociation energy decreases and the bond length increases.

In case of oxygen, O2  → O2+   + e-

Electron is lost from antibonding MO and the bond order increases from 2 to 2.5. As a result, bond dissociation energy increases but bond length decreases.

Answered by Vaibhav Chavan | 25th Aug, 2014, 11:01: AM

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