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between which two points of a concave mirror should an object be placed to obtain a magnification of -3 ?
Asked by ishitalamba18 | 15 Dec, 2020, 09:52: PM
We have mirror equation as :-  (1/v ) + (1/u ) = (1/f )  .................(1)

where v is mirror-to-image distance , u is mirror-to-object distance and f is focal length of mirror

magnification is given as,  m = -v/u  ................ (2)

if required magnification is -3 , then  -v/u = - 3    or v = 3u

If we substitute v = 3u , in mirror equation (1) , we get ,   (1/3u) + (1/u) = (1/f)  or   u = (4/3) f

Hence if mirror-to-object distance is (4/3)f , we get magnification -3

v = (4/3)f = 1.33 f

hence object should be placed between F and 2F , where F is focal point of mirror and 2F is centre of curvature.

Exact distance is (4/3)f
Answered by Thiyagarajan K | 16 Dec, 2020, 12:38: AM

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