CBSE Class 10 Answered
ARITHEMATIC PROGRESSION
Asked by chahat | 11 Mar, 2009, 12:29: AM
Expert Answer
Let the first term is a and common diff is d
so the nth term is given by
nth term =a+(n-1)d
Acc to question,
a+18d=3[a+5d]
2a=3d
a=3/2(d..).(i)
Next,
9th term =19(given)
So,
a+8d=19
(3/2)(d)+8d=19
(3d+16d)/2=19
d=2
a=3/2(d)=3
a=3
now, with a and d known, you can easily find the A.P.
Answered by | 11 Mar, 2009, 09:51: AM
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