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CBSE Class 10 Answered

ap
Asked by | 11 Jun, 2008, 01:31: PM
Expert Answer

The price of the equipment after 10 years is given by the following relation:

Price after 10 years = 60,000 - 60,000[0.15 + 0.135 + ........10 terms]

The terms in the bracket are an AP of 10 terms with the first term as 0.15 and the common diffrence as 0.015

The sum of n terms of an AP is given by

Sn = n/2[2a + (n-1)d]

Thus the sum of the first 10 terms would be:

S10 = 5[2*0.15 + 9*0.015]

Evalute the above expression and substitute in the orignal expression to get the price of the machine after 10 years.

Answered by | 18 Jun, 2008, 10:49: AM
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