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Asked by rs1702 | 04 Jan, 2019, 14:13: PM
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Since resistivity of material of wire_B is less than that of wire-A, Wire_A has to be thicker.
 
Equivqlent resistance Re is given by
 
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hece current drawn from battery is 6V/3Ω is 2A
 
Since all the resistance are connected in parallel, potenial difference across each resistance has to be 6V
 
Hence current through 30Ω resistance = 6/30 = 0.2 A
current through 10Ω resistance = 6/10 = 0.6 A
current through 5Ω resistance = 6/5 = 1.2 A
Answered by Thiyagarajan K | 05 Jan, 2019, 07:55: AM

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