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An object 5 cm in length is placed at a distance of 20 cm in front of a concave mirror of radius of curvature 30 cm. Find the position of the image ,it's nature and size
Asked by virender | 29 Jan, 2020, 05:21: PM
When the object lies along the principle axis, then its longitudinal magnification m = (v/u)2

where u is the mirror-to-object distance and v is mirror-to-image distance.

length of image Li = [  f / (u-f) ]2 Lo  .....................(1)

where f is focal length of mirror and Lo is length of object

position is obtained from mirror equation :-  (1/v) + (1/u) = 1/f  .......................(2)

if radius of curvature is 30 cm , then f = 15 cm

Hence from eqn.(2), we have, 1/v = (1/15) - (1/20) = (1/60)  or  v = 60 cm

lateral size Lis obtained from eqn.(1),  hence  Li = [ 15/ (20-15) ]2 × 5 = 45

image is magnified and real
Answered by Thiyagarajan K | 30 Jan, 2020, 08:36: AM

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