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An object 4 cm in size is placed at a distance of 25 cm from a concave mirror of focal length 15 cm. Find the position, nature and height of the image.
Asked by ishitalamba18 | 28 Nov, 2020, 07:53: PM
We have mirror equation that relates object-to-mirror distance u , image-to-mirror distance v and focal length of mirror f as

(1/v) + (1/u) = 1/f

(1/v) = (1/f) - (1/u) = (1/15) - (1/25) = 2/75

Hence v = 75/2 = 37.5 cm

magnicfiaction m = -v/u = -37.5/25 = -1.5 cm

if object size 4 cm , then image size ( -1.5 × 4 ) = -6 cm

Image is formed at 37.5 cm in front of mirror , Image is magnified by 1.5 times , Image size is 6 cm

Image is real and inverted.
Answered by Thiyagarajan K | 28 Nov, 2020, 08:22: PM

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