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An electric bulb rated for 200w and 100v is connected to a circuit having a 200v supply. What is the resistance R that must be put in series with the bulb so that the bulb draws 200w?
Rated power of the bulb is 200 W and operating voltage is 100 V.

Current drawn by the bulb = power/voltage = 200/100 = 2 A

Resistance = Voltage/current = 100/2 = 50 Ω

when this bulb is connected in 200 V supply, we need to ensure the current passing through this bulb is 2 A

total resistance required to get 2 A from 200 V supply = 200/2 = 100 Ω

Since resistance of bulb is 50 Ω , we need to add additional 50 Ω resistance in series.
Answered by Thiyagarajan K | 07 Mar, 2019, 11:36: AM

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