AN ASYRONOMICAL TELESCOPE CONSISTS OF TWO THIN LENSES 36 CM APART AND HAS NORMAL MAGNIFYING POWER 8.CALCULATE FOCAL LENGTH OF LENSES.

Asked by Ashok Bhokardankar | 13th Jun, 2011, 12:35: AM

Expert Answer:

Distance between the objective lens and the eyepiece of astronomical telescope = fo +  fe;
 
where fo = focal length of objective lens and fe = focal length of eye lens
Magnifying power, m = fo/fe;
 
36 = fo +  fe;
 
m = 8 = fo/fe;
 
36 = 8 fe + fe = 9 fe;
 
fe = 4 cm
 
and fo = 32 cm 

Answered by  | 13th Jun, 2011, 01:46: PM

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