Asked by MANOJKUMAR | 29th Apr, 2010, 10:25: AM
It's 11 km/s. Escape velocity doesn't depend upon angle of projection.
The intensity of the gravitational field will be zero, at the point where the gravitational force will be zero. Let the distance is x from small body.
G(100)(10000)/x2 = G(100)(10000)/(1-x)2
x2 = (1-x)2
x = 1/2 m.
(iii) More than 90°
Answered by | 29th Apr, 2010, 08:51: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number