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ABCD IS A TRAPEZIUM SUCH THAT AB IS PARALEL TO CD AND THE DIAGNLS INTERSECT AT A POINT 0.IF  OD=5CM, OB=7CM,AC=18CM, THEN THE DIFFERENCE BETWEEN THE LENGHTS OF OA AND OC IS EQUAL TO 1)3CM         2)6CM       3)8CM   4)12CM
Asked by seeni2005 | 21 Aug, 2020, 09:18: AM Expert Answer
In triangle OAB and triangle OCD,
Angle AOB = Angle COD ... (Vertically opposite angle)
Angle OAB = Angle OCD ... (Alternate angles)
So, triangle OAB is similar to triangle OCD ... (by AA similarity test)
Using the property of similarity i.e. corresponding sides of similar triangles are proportional, we have Answered by Renu Varma | 21 Aug, 2020, 11:17: AM

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