ABC is an isosceles triangle in which AB=AC, circumscribed about a circle.Prove that the base is bisected by the point of contact.
Asked by snehamapink | 18th Feb, 2012, 11:42: AM
Let the circle touch the sides AB, BC and CA of triangle at points R, Q, and P.
Answered by | 18th Feb, 2012, 04:48: PM
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