A wire of resistance 5 ohm s drawn out so that its length is increased to twice the original length.Calculate its new resistance.

Asked by jigyasa dwivedi | 24th May, 2012, 09:41: PM

Expert Answer:

Length got doubled 
 
pi (r12) l1 = pi (r22) l2
 
(r12) /  (r22) = 2
 
(r22) = (r12) /2
 
So resiatnace will be 4 times & it will be 5 * 4 = 20 ohms

Answered by  | 25th May, 2012, 10:23: AM

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