CBSE Class 10 Answered
A wire
of resistance 10 ohm is drawn out of so that the length is 3 has its original line calculate its new resistance
Asked by sandhushivanand2004 | 27 Dec, 2019, 20:28: PM
when the wire is drawn out so that its length increases 3 times of its original length L, its initial cross scection area A decrases.
Since volume is constant, L×A = 3L×An .......................(1)
where An is crosssection of wire after its length increased.
From eqn.(1), we get An = A/3
Let ρ be the resitivity of material of wire.
Hence changed resistance, Rn = ρ ×(3L)/ (A/3) = 9 (ρ L / A ) = 9 × 10 = 90 Ω
Answered by Thiyagarajan K | 28 Dec, 2019, 08:56: AM
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