A train accelerates uniformly from 18 km/h to 108 km/h in 25 s.Calculate : (1) acceleration (2) distance covered ?

Asked by nisha_vini29 | 22nd May, 2018, 11:22: PM

Expert Answer:

Initial speed u = 18 km/hr = 18 × (5/18) = 5 m/s ;  Final speed v = 108 km/hr = 108 × (5/18) = 30 m/s
 
acceleration a  is calculated using the formula " v = u+at " , where t is time in seconds. 
 
acceleration a = (v-u)/t = (30-5)/25 = 1 m/s2
 
Distance S is calculated using the equation S = u×t + (1/2)×a×t2 = 5×25 + (1/2)×1×25×25 = 437.5 m

Answered by Thiyagarajan K | 23rd May, 2018, 02:38: PM

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