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CBSE Class 9 Answered

a stone is released from the top of the tower of height 19.6 m calculate its final velocity just before touching the ground
Asked by mj2692076 | 31 Dec, 2021, 04:11: PM
Expert Answer

Initial Velocity  u=0
Fianl velocity v=?
Height, s=19.6m
g = 9.8 ms2 
 
By third equation of motion
 
v2u22gs
Where,
u = initial velocity of the stone
v = final velocity of the stone
s = height of the stone
g = acceleration due to gravity
 

v2=0+2×9.8×19.6
v2=384.16
 
v=19.6m/s

 
 

Answered by Ramandeep | 03 Jan, 2022, 05:01: PM

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