A stone is dropped into a well 44.1 m deep and the sound of splash is heard after 3.13 s. Find the speed of sound in air.

Asked by Topperlearning User | 19th Mar, 2015, 08:53: AM

Expert Answer:

Let t1 be the time taken by stone to reach the water surface in the well and t2 the time taken by sound of splash to travel upward from water surface in well to outer edge of the well.

Then total time t = t1 + t2 = 3.13 s
Given that the depth of water in well h = 44.1 m
We assume, buoyancy of water on stone is zero.

Answered by  | 19th Mar, 2015, 10:53: AM