# CBSE Class 8 Answered

**A rectangular park is 38 m long and 15 m wide. A path 3.5 m wide is constructed outside the park. Find the perimeter of the path.**

Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM

Expert Answer

The above data can be shown in a figure as follows:

Let PQRS represent the rectangular park and the shaded region represent the path 3.5 m wide.

Thus, to find the length AB and breadth BC, we have to add 3.5 m to both sides of rectangular park whose dimensions are 38 x 15

So, the length and breadth of the path are:

Length AB = (38 + 3.5 + 3.5) m = 45 m

Breadth BC = (15 + 3.5 + 3.5) m = 22 m

So, perimeter of the path = 2 x (l + b)

= 2 x (45 + 22)

= 2 x 67 = 134 m

Thus, perimeter of the path is 134 m.

Let PQRS represent the rectangular park and the shaded region represent the path 3.5 m wide.

Thus, to find the length AB and breadth BC, we have to add 3.5 m to both sides of rectangular park whose dimensions are 38 x 15

So, the length and breadth of the path are:

Length AB = (38 + 3.5 + 3.5) m = 45 m

Breadth BC = (15 + 3.5 + 3.5) m = 22 m

So, perimeter of the path = 2 x (l + b)

= 2 x (45 + 22)

= 2 x 67 = 134 m

Thus, perimeter of the path is 134 m.

Answered by | 04 Jun, 2014, 03:23: PM

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