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CBSE Class 12-science Answered

a particle starts from rest with constant acceleration, if first distance S is covered in time tthen the time taken to cover the next 2S distance is
Asked by sne271gha | 20 May, 2020, 11:00: PM
answered-by-expert Expert Answer
L e t a space b e space t h e space a c c e l e r a t i o n space o f space t h e space p a r t i c l e s equals u t plus 1 half a t squared u equals 0 s equals 1 half a t squared t equals square root of fraction numerator 2 s over denominator a end fraction end root minus negative negative negative negative left parenthesis 1 right parenthesis N o w space f o r space n e x t space 2 s space d i s tan c e T h e space t o t a l space d i s tan c e space f r o m space t h e space s t a r t i n g space w o u l d space b e space S plus 2 S 3 S equals u t plus 1 half a t squared u equals 0 t subscript 3 s end subscript equals square root of fraction numerator 6 S over denominator a end fraction end root t subscript 3 s end subscript equals square root of 3 square root of fraction numerator 2 S over denominator a end fraction end root O n space s u b s t i t u t i n g space left parenthesis 1 right parenthesis space w e space g e t t subscript 3 s end subscript equals square root of 3 t T i m e space t a k e n space t o space c o v e r space 2 s space d i s tan c e space w o u l d space b e t subscript 3 s end subscript minus t i. e square root of 3 t minus t t left parenthesis square root of 3 minus 1 right parenthesis
Answered by Utkarsh Lokhande | 21 May, 2020, 10:58: AM

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CBSE 12-science - Physics
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CBSE 12-science - Physics
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