A nail has 2metre square at one end,1/100m^2 and at the other end.  a force of 1000g. weight is applied on the first end calculate the pressure avthing on the wall? Value of g=10m/sec^2 

The area of first end of nail is 2 m²  

Area of other end is 1/100 = 10^-2 m² = 0.01 m² 

Force applied = 1000 gwt = 1000 × 10 = 10000 N ...(Since, g =10 m/s²)

Pressure is applied at first end. This means other end whose area is 0.01 m² is in contact with the wall. 

Thus, the pressure acting on a wall is 

P = Force/ Area = 10000/0.01 = 1000000= 10⁶ N/m²