CBSE Class 10 Answered
a motorist take 10 seconds to cover a distance of 20 metres and 15 seconds to cover a distance of 8 mrs find the uniform acceleration of car and velocity at the end of 15 second
Asked by sateeshkumarjan14 | 12 May, 2019, 10:35: AM
I assume initial speed of motor is u m/s, then the motor has travelled a distance 20 m at first 10 s
and moved a distance 8 m in next 15 seconds.
I also assume it is required to get acceleration a and speed after 15 seconds staring from initial time.
distance S travelled in first 10 s is given by, S = ut+(1/2)at2; 20 = 10u +(1/2)a×100 or u + 5a = 2 ..............(1)
speed v after 10 s is given by v = u+at ; v = u+10a
if 8 m distance is travelled in next 15 s, then 8 = (u+10a)15 + (1/2)a×225 or 15 u + (525/2)a = 8 ..................(2)
By solving eqn.(1) and eqn.(2), we get acceleration a = -44/375 m/s2 and u = 194/75 m/s
speed after 15 seconds, v = (194/75) -(44/375)×15 = 62/75 m/s = 0.83 m/s
Answered by Thiyagarajan K | 12 May, 2019, 12:24: PM
Application Videos
Concept Videos
CBSE 10 - Physics
Asked by ramkrushnaramkrushna1 | 07 Jul, 2024, 19:01: PM
CBSE 10 - Physics
Asked by mailtoparvathyprajith | 01 Jul, 2024, 13:16: PM
CBSE 10 - Physics
Asked by gs6070260 | 15 Jun, 2024, 20:45: PM
CBSE 10 - Physics
Asked by rv5238428 | 15 Jun, 2024, 19:43: PM
CBSE 10 - Physics
Asked by diljotsingh68641 | 08 Jun, 2024, 19:03: PM
CBSE 10 - Physics
Asked by jainvandan708 | 07 Jun, 2024, 12:06: PM
CBSE 10 - Physics
Asked by kk7629948076 | 03 Jun, 2024, 23:17: PM
CBSE 10 - Physics
Asked by agankitgupta938 | 18 Apr, 2024, 16:29: PM
CBSE 10 - Physics
Asked by infinityupgraded | 13 Apr, 2024, 08:17: AM