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a metal container is in the form of cylinder is surmounted by hemisphere of the same radius .the internal height of the cylinder is 7m and internal radius of the cylinder is 3.5m .calculate the total surface area of the internal surface excluding the base and find the internal volume of the container in m3
Asked by eswarandevi375 | 19 Nov, 2023, 03:06: PM
Figure shows the container which is a cylinder surmounted by a hemisphere .

Let d = 3.5 m be the internal diameter of cylinder and h = 7.0 m be the height of cylinder .

Inner surface area S1 of cylindrical part of container = ( π d h ) + (π/4) d2 = π d [  h + ( d2 / 4 ) ]

( First term of above expression for curved surface area and second term for bottom surface area )

Inner surface area s2 of hemispherical part of container = 2π (d/2)= π (d2 / 2 )

Total inner surface area = S1 + S2 = (110.6 + 19.2 ) m2 = 129.8 m2

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Inner volume V1 of cylindrical part of container = (π/4) d2 h

Inner volume V2 of hemispherical part of container = (2/3)π (d/2)3 = (1/12) π d3

Total Inner volume = V1 + V2 = 78.57 m3

Answered by Thiyagarajan K | 19 Nov, 2023, 04:30: PM

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Asked by eswarandevi375 | 19 Nov, 2023, 03:06: PM