a gaseous mixture contains oxygen and nitrogen in the ratio of 1:4 by weight. Therefore the ratio of their no. of molecules is......?

Asked by ayushikas | 21st May, 2011, 09:23: PM

Expert Answer:

Let us assume that the mass of oxygen is x 
therefore mass of nitrogen is 4x 
no. of moles of oxygen present in mixture 
= given mass / molecular mass = x/32 
no. of moles of nitrogen present = 4x/28 
therefore ratio of their no. of molecules 
= (x/32) : (4x/28) 
=

Answered by  | 21st May, 2011, 04:06: PM

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