A charge Q is uniformly distributed over a rod of length l.Consider a hypothetical cube of edge L with the centre of the cube at one end of the rod.Find th minimum possible flux of the electric field through the entire surface of the cube.

Asked by Balbir | 8th Apr, 2017, 02:46: PM

Expert Answer:

begin mathsize 12px style The space length space of space the space rod space is space straight L space and space the space side space of space the space cube space is space also space straight L.
When space one space end space of space the space rod space is space at space the space centre space of space the space cube comma space the space effective space length
of space the space rod space for space which space charges space induce space flux space on space the space cube space is space straight L divided by 2.

Now comma space according space to space Gauss apostrophe space law comma
straight ϕ equals straight q subscript enc over straight epsilon subscript 0
As space half space length space is space inside space the space cube comma space charge space enclosed space by space the space cube space is space straight Q divided by 2.
therefore straight ϕ equals fraction numerator straight Q over denominator 2 straight epsilon subscript 0 end fraction end style

Answered by Romal Bhansali | 10th Apr, 2017, 11:45: AM