CBSE Class 9 Answered
A ball is thrown vertically upwards and rises to a height of 126.5 m. Calculate the
(i) velocity by which the ball was thrown upwards and
(ii) the time taken by the ball to reach the highest point. (Given is g = 9.8 ms–²)
At Least 100 to 150 words
Asked by Aryungupta.espn | 30 Dec, 2019, 15:34: PM
h = 126.5 m
i)
v2 - u2 = 2as
As the ball is moving against the gravity when thrown upward,
v2 - u2 = 2gh
Thus,
0 = u2 + 2 (-9.8) × (126.5) ... (negative sign of 'g' indicate that the object is moving against the gravity)
u2 = 2479.5
Thus,
u = 49.79≈ 50 m/s
Thus, the velocity by which the ball must be thrown upward is 49.79 m/s
ii) time taken by the ball to reach the highest point is given as,
v = u + gt
Thus,
0 = 49.79 + (-9.8) x t
Thus,
t = 5.08 s
Answered by Shiwani Sawant | 30 Dec, 2019, 18:39: PM
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