Request a call back

A ball is thrown vertically upwards and rises to a height of 126.5 m. Calculate the (i) velocity by which the ball was thrown upwards and (ii) the time taken by the ball to reach the highest point. (Given is g = 9.8 ms–²) At Least 100 to 150 words
Asked by Aryungupta.espn | 30 Dec, 2019, 03:34: PM
h = 126.5 m

i)
v2 - u2 = 2as
As the ball is moving against the gravity when thrown upward,

v2 - u2 = 2gh
Thus,
0 = u2 + 2 (-9.8) × (126.5) ... (negative sign of 'g' indicate that the object is moving against the gravity)
u2 =  2479.5
Thus,
u = 49.79≈ 50 m/s

Thus, the velocity by which the ball must be thrown upward is 49.79 m/s

ii) time taken by the ball to reach the highest point is given as,
v = u + gt
Thus,
0 = 49.79 + (-9.8) x t
Thus,
t = 5.08 s
Answered by Shiwani Sawant | 30 Dec, 2019, 06:39: PM

## Concept Videos

CBSE 9 - Physics
CBSE 9 - Physics
Asked by munendramishra478 | 12 Jul, 2022, 08:42: PM
CBSE 9 - Physics
Asked by rk7213908 | 31 Mar, 2022, 12:28: PM
CBSE 9 - Physics
Asked by rk7213908 | 21 Feb, 2022, 04:48: PM
CBSE 9 - Physics
Asked by mannatjohn920 | 15 Feb, 2022, 09:57: AM