A bag contains 5 red and 4 black balls and another bag contains 4 red and 4 black balls. Two balls are drawn from the first bag and one from the second bag. Find the probability that out of three balls, two are red and one is black.

Asked by siddarth | 6th Jun, 2013, 06:27: PM

Expert Answer:

Probability that out of the 3 balls, 2 are red and one is black would be equivalent to the sum of probability of drawing either a red and black ball from the first bag and then drawing a red bag from the second one and probability of drawing 2 red balls from the first bag and then drawing a black ball from the second bag. 
 
So P(RRB)  = R(RB from first bag)*P(R from the second bag) + P(RR from the first bag) * P(B from the second bag)
 

Answered by  | 18th Jun, 2013, 02:51: AM

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