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CBSE Class 11-science Answered

5 L of an alkane requires 25 L of oxygen for its complete combustion . If all volumes as measured at constant temperature an dpressure , the alkane is? A-Butane B-Isobutane C-Propane D-Ethane
Asked by Apoorva | 27 Apr, 2019, 05:20: PM
answered-by-expert Expert Answer
Option C is correct.
 
The combustion reaction  of alkane is
 
space space space space space space space straight C subscript straight n straight H subscript 2 straight n plus 2 space end subscript plus open parentheses fraction numerator 3 straight n plus space 1 over denominator 2 end fraction close parentheses straight O subscript 2 space space rightwards arrow nCO subscript 2 space space plus open parentheses straight n plus 1 close parentheses straight H subscript 2 straight O space space space space space space space space space space space space space 5 space lit space space space space space space space space space 25 space lit space space space space space space space space space space space space space space space space space space space At space constant space temperature space and space pressure space space space space space space space space space space space space space Volume space proportional to space Number space of space moles space space space space space space space space space space space space space straight n subscript alkane space space equals space open parentheses fraction numerator 2 over denominator 3 straight n plus 1 end fraction close parentheses cross times nO subscript 2 space space space space space space space space space space space space space space space space space space space space space space 5 space equals space space open parentheses fraction numerator 2 over denominator 3 straight n plus 1 end fraction close parentheses cross times 25 space space space space space space space space space space space space space space space space space space space space space space space straight n space equals space 3 As n = 3  os  is 3 carbon alkane, propane.
Answered by Varsha | 27 Apr, 2019, 06:18: PM

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