ICSE Class 10 Answered
3(2x-1)^2+5(2x-1)-4=0
Asked by shruthinair5848.10sdatl | 01 Jul, 2020, 22:09: PM
Take 2x-1=y, the equation becomes
3y2+5y-4=0
This is in the form of a quadratic equation
We have a=3, b=5 and c=-4
Let's solve this using the quadratic formula method
![y equals fraction numerator negative 5 plus-or-minus square root of left parenthesis 5 right parenthesis squared minus 4 left parenthesis 3 right parenthesis left parenthesis negative 4 right parenthesis end root over denominator 2 cross times 3 end fraction equals fraction numerator negative 5 plus-or-minus square root of 25 plus 48 end root over denominator 6 end fraction equals fraction numerator negative 5 plus-or-minus square root of 73 over denominator 6 end fraction
rightwards double arrow 2 x minus 1 equals fraction numerator negative 5 plus-or-minus square root of 73 over denominator 6 end fraction
rightwards double arrow 2 x equals fraction numerator negative 5 plus-or-minus square root of 73 over denominator 6 end fraction plus 1 equals fraction numerator 1 plus-or-minus square root of 73 over denominator 6 end fraction
rightwards double arrow x equals fraction numerator 1 plus-or-minus square root of 73 over denominator 12 end fraction](https://images.topperlearning.com/topper/tinymce/cache/5e21552a4554c0b90aa6ae91f80e8ed2.png)
Answered by Renu Varma | 02 Jul, 2020, 10:55: AM
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