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CBSE Class 12-science Answered

29th sum plz
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Asked by lovemaan5500 | 19 Aug, 2019, 11:21: PM
answered-by-expert Expert Answer
 
See the marked points X and Y in the given circuit that was shown left side of the figure.
The given circuit is redrawn in right side figure to show that all the three resistances are connected in parallel.
Marked points X and Y will help to realize the circuit redrawn.
 
If Req is the equivalent resistance of the resistors combination,
 
then  (1/Req) = (1/R) + (1/2R) +(1/3R) =  (6R2 + 3R2 + 2R2 )/ (6R3)    or  Req = (6/11)R Ω
 
if 2A is current in the circuit,   then 2 [ (5/11) + (6/11) ]R = 12 V     or   R  = 6 Ω
Answered by Thiyagarajan K | 20 Aug, 2019, 09:22: AM

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