ICSE Class 10 Answered

25x*x( 25 root 2) +6001x-249300=0

Asked by Mannat | 08 May, 2016, 08:30: PM

Expert Answer

C o n s i d e r space t h e space g i v e n space q u a d r a t i c space e q u a t i o n 25 x squared open parentheses 25 square root of 2 close parentheses plus 6001 x minus 249300 equals 0 H e r e space a equals 625 square root of 2 comma space b equals 6001 space a n b d space c equals negative 249300 T h u s comma space b y space a p p l y i n g space q u a d r a t i c space f o r m u l a comma space w e space h a v e comma x equals fraction numerator negative b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction rightwards double arrow x equals fraction numerator negative 6001 plus-or-minus square root of 6001 squared minus 4 cross times 625 square root of 2 cross times open parentheses negative 249300 close parentheses end root over denominator 2 cross times 625 square root of 2 end fraction rightwards double arrow x almost equal to fraction numerator negative 6001 plus-or-minus 30289 over denominator 2 cross times 625 square root of 2 end fraction rightwards double arrow x almost equal to 13.74 space o r space x almost equal to negative 20. F i n d i n g space t h e space s o l u t i o n space o f space t h i s space e q u a t i o n space b y space f a c t o r i z a t i o n space i s space d i f f i c u l t space a s space i t space i s space h a v i n g space i r r a t i o n a l space c o e f f i e c i e n t s.

Answered by Vimala | 08 May, 2016, 10:33: PM

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