1.An insurance companyinsured 2000 scooter drivers,4000 car drivers & 6000 truck drivers.The probablity of an accidents are 0.01,0.03 & 0.15.One of the insured person meetswith an accident.What is the probablity that he is a scotter driver?

Asked by Prakash | 21st Nov, 2017, 12:17: AM

Expert Answer:

begin mathsize 16px style Let space straight A subscript 1 space be space the space scooter space driver
straight A subscript 2 space be space the space car space driver
straight A subscript 3 space be space the space truck space driver.
Total space number space of space drivers equals 2000 plus 4000 plus 6000 equals 12000
straight P open parentheses space straight A subscript 1 space close parentheses equals 2000 over 12000 equals 2 over 12
straight P open parentheses straight A subscript 2 close parentheses equals 4000 over 12000 equals 4 over 12
straight P open parentheses straight A subscript 3 close parentheses equals 6000 over 12000 equals 6 over 12
straight P open parentheses straight E divided by straight A subscript 1 close parentheses equals straight P open parentheses scooter space driver space met space with space an space accident close parentheses equals 0.01
straight P open parentheses straight E divided by straight A subscript 1 close parentheses equals straight P open parentheses car space driver space met space with space an space accident close parentheses equals 0.03
straight P open parentheses straight E divided by straight A subscript 3 close parentheses equals straight P open parentheses truck space driver space met space with space an space accident close parentheses equals 0.15
Using space Baye apostrophe straight s space theorem comma
we space get
fraction numerator begin display style 2 over 12 end style cross times 0.01 over denominator 1 over 12 cross times 0.01 plus 4 over 12 cross times 0.03 plus 6 over 12 cross times 0.15 end fraction equals 1 over 52

end style

Answered by Sneha shidid | 30th Nov, 2017, 10:08: AM

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