CBSE Class 11-science Answered
1.84 gram of a mixture of calcium carbonate and magnesium carbonate is strongly heated till no further loss of mass takes place. The residue weights 0.96 g. Calculate the percentage composition of mixture.
Asked by Manoj | 08 Jul, 2013, 09:03: PM
Expert Answer
CaCO3 ? CaO + CO2
100gms 56g 44g
1. 100gm CaCO3 forms 56 gms CaO
X gm CaCO3 forms 56.x/100 = 0.56x gm CaO
2. MgCO3 ? MgO+ CO2
84g 40g 44g
84g MgCO3 forms 40g MgO
Therefore, (1.84 - x)g of MgCO3 forms 40 x (1.84 - x) / 84 g MgO
Total Mass of Cao + MgO from the above
= 0.56x + 40 x (1.84 - x) / 84 = 0.96g (given)
Hence, x = 1
Mass of CaCO3 = 1gm
Mass of MgCO3 = (1.84 - 1)
= 0.84g
Percentage of CaCO3 in the mixture = 1 x 100 / 1.84
= 54.35%
Percentage of MgCO3 in the mixture = 100 - 54.35 = 45.65%
Answered by | 10 Jul, 2013, 02:03: AM
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