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CBSE Class 10 Answered

15 no please solve it
Asked by nisargrpatel99 | 31 May, 2020, 07:24: AM
Expert Answer
An alpha particle is projected perpendicular to uniform electric field.A force will act on the alpha particle which deviates it.
The force acting on the alpha particle in horizontal direction is given by
F equals q E F equals 2 e cross times E l e t apostrophe s space c o n s i d e r space t h e space m a s s space o f space t h e space a l p h a space p a r t i c l e space 4 m a subscript x equals fraction numerator 2 e E over denominator 4 m end fraction minus negative negative negative negative negative left parenthesis space a l p h a space p a r t i c l e space h a s space c h a r g e space 2 e space a n d space m a s s space 4 m right parenthesis F i n a l space s p e e d space o f space t h e space a l p h a space p a r t i c l e space i n space h o r i z o n t a l space d i r e c t i o n space i s v subscript x equals u subscript x plus a subscript x t 3 v subscript 0 C o s 60 to the power of o equals 0 plus fraction numerator 2 e E over denominator 4 m end fraction t minus negative negative negative negative left parenthesis 1 right parenthesis N o w space d i s tan c e space t r a v e l l e d space b y space t h e space a l p h a space p a r t i c l e space i n space h o r i z o n t a l space d i r e c t i o n space i s space S subscript x equals u subscript x t plus 1 half a subscript x t squared d equals 0 cross times t plus 1 half fraction numerator 2 e E over denominator 4 m end fraction t squared minus negative negative negative negative negative negative left parenthesis 2 right parenthesis
Solving these two equation will give the value of E
Answered by Utkarsh Lokhande | 31 May, 2020, 04:28: PM

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