1.5¯+2.6¯+3.7¯

Asked by sabarnakrish | 30th May, 2020, 05:42: PM

Expert Answer:

1.5+2.6+3.7+4.8+....
Here, 2.6-1.5 = 1.1
3.7-2.6 = 1.1
4.8-3.7 = 1.1
and so on
Difference between every 2 consecutive terms is costant.
Therefore, this forms an AP with first term a=1.5 and common difference d=1.1
Sum of n terms of an AP is given by
Sn = n/2[2a + (n-1)d] = n/2[3+(n-1)1.1]

Answered by Renu Varma | 1st Jun, 2020, 05:31: PM

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