CBSE Class 10 Answered
1.5¯+2.6¯+3.7¯
Asked by sabarnakrish | 30 May, 2020, 05:42: PM
1.5+2.6+3.7+4.8+....
Here, 2.6-1.5 = 1.1
3.7-2.6 = 1.1
4.8-3.7 = 1.1
and so on
Difference between every 2 consecutive terms is costant.
Therefore, this forms an AP with first term a=1.5 and common difference d=1.1
Sum of n terms of an AP is given by
Sn = n/2[2a + (n-1)d] = n/2[3+(n-1)1.1]
Answered by Renu Varma | 01 Jun, 2020, 05:31: PM
Application Videos
Concept Videos
CBSE 10 - Maths
Asked by bkhaiwangkonyak | 07 Mar, 2023, 04:35: PM
CBSE 10 - Maths
Asked by sakshinde95 | 23 Jan, 2023, 05:50: PM
CBSE 10 - Maths
Asked by d7016880266 | 20 Jan, 2023, 08:14: PM
CBSE 10 - Maths
Asked by jaiprakashprasadr | 17 Jul, 2022, 11:03: PM
CBSE 10 - Maths
Asked by Keerthanaambika48 | 13 Jul, 2021, 09:44: AM
CBSE 10 - Maths
The sum of the first 7 terms of an A.P is 182 if its 4th ans 17th terms are in ratio 1:5 find the Ap
Asked by madhutowari | 28 Jun, 2021, 07:56: PM
CBSE 10 - Maths
Asked by maulaali35 | 24 Oct, 2020, 08:00: AM
CBSE 10 - Maths
Asked by Anubhavjain599 | 25 Aug, 2020, 10:16: PM
CBSE 10 - Maths
Asked by seeni2005 | 17 Aug, 2020, 12:42: AM
CBSE 10 - Maths
Asked by Deepakaryan571 | 09 Aug, 2020, 12:18: PM