Request a call back

12 cm is the radius of curvature of concave mirror. The image obtained by it is real and has magnification of the 3/2. Find object distance
Asked by navdurgacrane1997 | 16 Jul, 2018, 08:50: PM
focal length f of concave mirror = 1/2 of radius of curvature = 12/2 = 6 cm .

magnification of mirror, m = -v/u = -1.5  ..............(1)
where v is image distance and u is object distance
(it is given that image is real. In concave mirror real images are inverted, hence -ve sign i.e. -1.5 is used in eqn.(1) )

from eqn.(1) , v = 1.5 u ................(2)

we have mirror eqn.,
Substituting value of f and using eqn.(2), eqn.(3) becomes :
solving for u in the eqn.(4), we get u = 10 cm
Answered by Thiyagarajan K | 17 Jul, 2018, 04:46: PM

## Application Videos

CBSE 10 - Physics
Asked by shrilakshmimunoli | 01 Mar, 2024, 01:15: AM
CBSE 10 - Physics
Asked by khajannirwan | 27 Feb, 2024, 10:20: PM
CBSE 10 - Physics
Asked by sailakshmi.avinesh | 13 Feb, 2024, 07:03: AM
CBSE 10 - Physics
Asked by sakshikatewa0 | 08 Feb, 2024, 12:48: PM
CBSE 10 - Physics
Asked by saurabhjd527 | 30 Jan, 2024, 07:55: PM
CBSE 10 - Physics