Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

12 cm is the radius of curvature of concave mirror. The image obtained by it is real and has magnification of the 3/2. Find object distance 
Asked by navdurgacrane1997 | 16 Jul, 2018, 20:50: PM
answered-by-expert Expert Answer
focal length f of concave mirror = 1/2 of radius of curvature = 12/2 = 6 cm .
 
magnification of mirror, m = -v/u = -1.5  ..............(1)
where v is image distance and u is object distance
(it is given that image is real. In concave mirror real images are inverted, hence -ve sign i.e. -1.5 is used in eqn.(1) )
 
from eqn.(1) , v = 1.5 u ................(2)
 
we have mirror eqn.,  begin mathsize 12px style 1 over v space plus space 1 over u space equals space 1 over f space................. left parenthesis 3 right parenthesis end style
Substituting value of f and using eqn.(2), eqn.(3) becomes :  begin mathsize 12px style fraction numerator 2 over denominator 3 u end fraction plus 1 over u space equals space 1 over 6 space............... left parenthesis 4 right parenthesis end style
solving for u in the eqn.(4), we get u = 10 cm
Answered by Thiyagarajan K | 17 Jul, 2018, 16:46: PM
CBSE 10 - Physics
Asked by sambhoorai | 27 Jul, 2024, 14:20: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by ramkrushnaramkrushna1 | 07 Jul, 2024, 19:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by kk7629948076 | 03 Jun, 2024, 23:17: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by agankitgupta938 | 18 Apr, 2024, 16:29: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by infinityupgraded | 13 Apr, 2024, 08:17: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Are You a Teacher or a Parent Seeking Customised Tests? Click here
×