CBSE Class 11-science Answered
1^2 +2.2^2+3^3+2.2^4+5^2+5^2+2.6^2 ........ is n(n+1)^2/2 when "n" is even . What is the sum when n is odd?
Asked by | 04 Nov, 2013, 11:03: PM
Expert Answer
When n is odd, last term will be n^2.
Thus,
Sum = 1^2 +2.2^2+3^3+2.2^4+5^2+2.6^2 ... + 2.(n-1)^2 + n^2
= [(n-1)(n)^2]/2 + n^2 [Replacing n by (n - 1)]
= [n^3 + n^2]/ 2 = [n^2(n+1)]/2
Answered by | 04 Nov, 2013, 11:29: PM
Application Videos
Concept Videos
CBSE 11-science - Maths
Asked by cubesneha.2005 | 07 Feb, 2024, 12:55: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by hridayjayaram085 | 31 Jan, 2024, 10:53: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by prashantbharati75 | 29 Sep, 2023, 09:30: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Bhaveshkr211 | 30 Jul, 2023, 05:20: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by sakshirana374 | 24 Jul, 2022, 05:39: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by sanjuktamukherjee165 | 24 Oct, 2021, 11:04: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by rahulksinha200 | 16 Oct, 2021, 02:08: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Vibhorjarora798 | 21 Aug, 2021, 05:43: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by shivangkarol | 16 Jun, 2021, 01:18: PM
ANSWERED BY EXPERT