# FRANK Solutions for Class 9 Maths Chapter 17 - Pythagoras Theorem

Revise Frank Solutions for ICSE Class 9 Mathematics Chapter 17 Pythagoras Theorem on TopperLearning. As you revise, you may come across problems asking you to find the area of a right-angled triangle. The chapter solutions by our experts will help you use the Pythagoras theorem step-by-step to find the right answer.

Frank textbook solutions for ICSE Class 9 Maths also includes model answers on methods to find the length of the side of a triangle. Practise similar problems by going through our Selina solutions as well. For revisiting the basics, check our e-learning concept videos available 24x7 on our study portal.

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## Chapter 17 - Pythagoras Theorem Exercise Ex. 17.1

Question 1 Solution 1 Question 2 Solution 2 Question 3 Solution 3 Question 4 Solution 4 Question 5 Solution 5 Question 6 Solution 6 Question 7 Solution 7 Question 8 Solution 8 Question 9 Solution 9 Question 10 Solution 10 Question 11 Solution 11 Question 12

In ABC, AD is perpendicular to BC. Prove that

AB2 + CD2 = AC2 + BD2

Solution 12  Question 13 Solution 13  Question 14

From a point O in the interior of a ABC, perpendicular OD, OE and OF are drawn to the sides BC, CA and AB respectively. Prove that:

a. AF2 + BD2 + CE2 = OA2 + OB2 + OC2 - OD2 - OE2 - OF2

b. AF2 + BD2 + CE2 = AE2 + CD2 + BF2

Solution 14  Question 15

In a triangle ABC, AC > AB, D is the midpoint BC, and AE BC. Prove that: Solution 15   Question 16 Solution 16 Question 17 Solution 17 Question 18 Solution 18 Question 19 Solution 19 Question 20 Solution 20 Question 21  Solution 21  Question 22

Ina right-angled triangle ABC, ABC = 90°, AC = 10 cm, BC = 6 cm and BC produced to D such CD = 9 cm. Find the length of AD.

Solution 22  Question 23

In the given figure. PQ = PS, P = R = 90°. RS = 20 cm and QR = 21 cm. Find the length of PQ correct to two decimal places. Solution 23  Question 24

In a right-angled triangle PQR, right-angled at Q, S and T are points on PQ and QR respectively such as PT = SR = 13 cm, QT = 5 cm and PS = TR. Find the length of PQ and PS.

Solution 24  Question 25

PQR is an isosceles triangle with PQ = PR = 10 cm and QR = 12 cm. Find the length of the perpendicular from P to QR.

Solution 25  Question 26

In a square PQRS of side 5 cm, A, B, C and D are points on sides PQ, QR, RS and SP respectively such as PA = PD = RB = RC = 2 cm. Prove that ABCD is a rectangle. Also, find the area and perimeter of the rectangle.

Solution 26  ### STUDY RESOURCES

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