# FRANK Solutions for Class 9 Maths Chapter 20 - Constructions of Quadrilaterals

Revise some geometry Frank Solutions for ICSE Class 9 Mathematics Chapter 20 Constructions of Quadrilaterals. Be it a trapezium or a parallelogram, go through the step-wise instructions to construct a quadrilateral. Our chapter-wise textbook solutions include model answers by experts that build your skills for doing well in your Maths exam.

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## Chapter 20 - Constructions of Quadrilaterals Exercise Ex. 20.1

Question 1
Solution 1

Question 2
Solution 2
Question 3
Solution 3
Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11
Solution 11
Question 12
Solution 12
Question 13
Solution 13
Question 14(a)

Construct a rectangle ABCD, when

AD = 3.2cm and diagonal BD = 5.5cm. Measure CD.

Solution 14(a)

Steps of construction:

1. Draw AD = 3.2 cm
3. With D as centre and radius BD = 5.5 cm, draw an arc to cut AX at point B.
4. Join BD.
5. With B as centre and radius 3.2 cm draw an arc and with D as centre and radius = AB, draw another arc to cut the previous arc at C.
6. Join BC and CD.

Thus, ABCD is the required rectangle.

CD = 4.5 cm

Question 14(b)

Construct a rectangle ABCD, when

AB = 5cm and BC = 6.2cm.

Solution 14(b)

Steps of construction:

1. Draw BC = 6.2 cm
2. Through B, draw BP such that B = 90°
3. From BP, cut BA = 5 cm
4. With A and C as centres and radii 6.2 cm and 5 cm respectively, draw arcs cutting each other at D.

Thus, ABCD is the required triangle.

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18(a)

Construct a rectangle PQRS, when its

Area = 21 cm2 and length = 4.2cm

Solution 18(a)

Since area of rectangle = 21 cm2

And, length = 4.2 cm

Breadth = Area ÷ Length = 21 ÷ 4.2 = 5 cm

Steps of construction:

1. Draw BC = 5 cm
2. Through B, draw BP such that B = 90°
3. From BP, cut BA = 4.2 cm
4. With A and C as centres and radii 5 cm and 4.2 cm respectively, draw arcs cutting each other at D.

Thus, ABCD is the required triangle.

Question 18(b)

Construct a rectangle PQRS, when its

Area = 33.8cm2 and breadth = 6.5cm

Solution 18(b)

Since area of rectangle = 33.8 cm2

Length = Area ÷ Breadth = 33.8 ÷ 6.5 = 5.2 cm

Steps of construction:

1. Draw BC = 6.5 cm
2. Through B, draw BP such that B = 90°
3. From BP, cut BA = 5.2 cm
4. With A and C as centres and radii 6.5 cm and 5.2 cm respectively, draw arcs cutting each other at D.

Thus, ABCD is the required triangle.

Question 19
Solution 19
Question 20
Solution 20

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