Chapter 20 : Constructions of Quadrilaterals - Frank Solutions for Class 9 Maths ICSE

Mathematics in ICSE Class 9 is one of the most challenging and trickiest subjects of all. It includes complex topics such as logarithms, expansions, indices and Pythagoras Theorem which are difficult to understand for an average student. TopperLearning provides study materials for ICSE Class 9 Mathematics to make the subject easy and help students to clear all their concepts. Our study materials comprise numerous video lessons, question banks, revision notes and sample papers which help achieve success in the examination.

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Chapter 20 - Constructions of Quadrilaterals Excercise Ex. 20.1

Question 1
Solution 1

Question 2
Solution 2
Question 3
Solution 3
Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11
Solution 11
Question 12
Solution 12
Question 13
Solution 13
Question 14

Construct a rectangle ABCD, when

AD = 3.2cm and diagonal BD = 5.5cm. Measure CD.

Solution 14

Steps of construction:

  1. Draw AD = 3.2 cm
  2. Draw XAD = 90°.
  3. With D as centre and radius BD = 5.5 cm, draw an arc to cut AX at point B.
  4. Join BD.
  5. With B as centre and radius 3.2 cm draw an arc and with D as centre and radius = AB, draw another arc to cut the previous arc at C.
  6. Join BC and CD.

Thus, ABCD is the required rectangle.

CD = 4.5 cm

 

Question 15

Construct a rectangle ABCD, when

AB = 5cm and BC = 6.2cm.

Solution 15

Steps of construction:

  1. Draw BC = 6.2 cm
  2. Through B, draw BP such that B = 90°
  3. From BP, cut BA = 5 cm
  4. With A and C as centres and radii 6.2 cm and 5 cm respectively, draw arcs cutting each other at D.
  5. Join AD and CD.

Thus, ABCD is the required triangle.

 

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Construct a rectangle PQRS, when its

Area = 21 cm2 and length = 4.2cm

Solution 19

Since area of rectangle = 21 cm2

And, length = 4.2 cm

Breadth = Area ÷ Length = 21 ÷ 4.2 = 5 cm

Steps of construction:

  1. Draw BC = 5 cm
  2. Through B, draw BP such that B = 90°
  3. From BP, cut BA = 4.2 cm
  4. With A and C as centres and radii 5 cm and 4.2 cm respectively, draw arcs cutting each other at D.
  5. Join AD and CD.

Thus, ABCD is the required triangle.

 

Question 20

Construct a rectangle PQRS, when its

Area = 33.8cm2 and breadth = 6.5cm

Solution 20

Since area of rectangle = 33.8 cm2

And, breadth = 6.5 cm

Length = Area ÷ Breadth = 33.8 ÷ 6.5 = 5.2 cm

Steps of construction:

  1. Draw BC = 6.5 cm
  2. Through B, draw BP such that B = 90°
  3. From BP, cut BA = 5.2 cm
  4. With A and C as centres and radii 6.5 cm and 5.2 cm respectively, draw arcs cutting each other at D.
  5. Join AD and CD.

Thus, ABCD is the required triangle.

Question 21
Solution 21
Question 22
Solution 22

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