CBSE Class 11-science Answered
Water is flowing with a speed of 4 m/s in a horizontal pipe of non-uniform area of cross-section decreasing from 0.04 m² to 0.01 m² at pressure 40 x 104 Pa. What will be the pressure at narrower end?
Asked by Topperlearning User | 31 Jul, 2014, 03:30: PM
Expert Answer
v1 = 4 m/s, a1 = 0.04 m², P1 = 40 x 104 Pa
a2 = 0.01 m², P2 = ?
According to equation of continuity, we have
a1v1 = a2v2
v2 = a1v1 / a2 = 0.04 x 4/ 0.01 = 16 m/s
According to Bernoulli's theorem, we have
P1+ ½ρv12 = P2 + ½ρv22
P2 = P1+ ½ρ(v12 - v22) = 40 x 104 + ½ x 10³ (4² - 16²)
= 40 x 104 - ½ x 10³ x 240
= (400 - 120) x 10³
= 280 x 10³ Pa
Answered by | 31 Jul, 2014, 05:30: PM
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