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Two trains T1 and T2 simultaneously start towards
each other at speeds of 40 km/hr and 60 km/hr
respectively. An eagle is sitting on the engine of
train T1. The moment the trains start, the eagle
starts flying towards the second train. Immediately,
on reaching the second train, the eagle heads back
towards the first train. Immediately on reaching the
first train, the eagle reverses the direction and starts
flying towards the second train. This process
continues till the two trains meet. If the distance
between the trains is 200 km and the speed of the
eagle is 80 km/hr, what is the total distance
travelled by the eagle in the forward direction (i.e.,
in the direction towards the second train)?
Asked by raviwarma7086 | 22 Dec, 2023, 02:36: PM
Expert Answer
Initial distance between trains = 200 km
Train T1 moves towards train T2 with speed 40 km/hr . Train T2 moves towards train T1 with speed 60 km/hr.
Hence relative speed of each train with respect to other train is 100 km/hr.
Time taken for the trains to meet = distance / ( relative speed) = 200 km / ( 100 km/hr ) = 2 hour.
If Eagle flies with speed 80 km/hr , then total distance travelled by eagle = (80 km/hr ) × 2 hour = 160 km
Half of above 160 km is travelled by eagle from T1 to T2 .
Hence distance travlled by eagle from T1 to T2 = 80 km
Answered by Thiyagarajan K | 22 Dec, 2023, 03:18: PM
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