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Two trains T1 and T2 simultaneously start towards each other at speeds of 40 km/hr and 60 km/hr respectively. An eagle is sitting on the engine of train T1. The moment the trains start, the eagle starts flying towards the second train. Immediately, on reaching the second train, the eagle heads back towards the first train. Immediately on reaching the first train, the eagle reverses the direction and starts flying towards the second train. This process continues till the two trains meet. If the distance between the trains is 200 km and the speed of the eagle is 80 km/hr, what is the total distance travelled by the eagle in the forward direction (i.e., in the direction towards the second train)?
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Asked by raviwarma7086 | 22 Dec, 2023, 02:36: PM
answered-by-expert Expert Answer

Initial distance between trains = 200 km

Train T1 moves towards train T2 with speed 40 km/hr . Train T2 moves towards train T1 with speed 60 km/hr.

Hence relative speed of each train with respect to other train is 100 km/hr.

Time taken for the trains to meet = distance / ( relative speed) = 200 km / ( 100 km/hr ) = 2 hour.

If Eagle flies with speed 80 km/hr , then total distance travelled by eagle = (80 km/hr ) × 2 hour = 160 km

Half of above 160 km is travelled by eagle from T1 to T2 .

Hence distance travlled by eagle from T1 to T2 = 80 km

Answered by Thiyagarajan K | 22 Dec, 2023, 03:18: PM

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