CBSE Class 10 Answered
triangle
Asked by suchet_r | 30 Aug, 2009, 08:03: PM
Expert Answer
Let ΔPQR be the right angled triangle, and PQR = 90,
Area of an equilateral triangle = 3x(Side)2/4
The area of equilateral triangle on side PQ = 3xPQ2/4
The area of equilateral triangle on side QR = 3xQR2/4
The area of equilateral triangle on side PR = 3xPR2/4
Using Pythagoras' Theorem,
PR2 = PQ2 + QR2,
Multiplying both sides by 3/4
(3/4)PR2 = (3/4)PQ2 + (3/4)QR2,
Area of E. triangle on hypotenuse, PR = Area of E. triangle on side PQ + Area of E. triangle on side QR ]
Regards,
Team,
TopperLearning.
Answered by | 31 Aug, 2009, 01:03: AM
CBSE 10 - Maths
Asked by s.sreeram | 11 Mar, 2010, 08:14: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:08: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:05: PM
ANSWERED BY EXPERT