CBSE Class 10 Answered
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Solution to Q 6 of Exercise 12.3 of NCERT.
R = 32 cm
The side of an equilateral triangle circumscribed in a circle of radius R, is given by,
Area of the equilateral triangle = (3/4)side2
= 1330.17 cm2
Area of circle = 3.14x32x32 = 3215.36 cm2
Area of design = Area of circle - Area of triangle = 3215.36 - 1330.17 = 1885.2 cm2