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CBSE Class 10 Answered

plz answer soon tomorrow is exam plzzzzzzzzzzz
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
Expert Answer

Please post queries individually.

Solution to Q 6 of Exercise 12.3 of NCERT.

R = 32 cm

The side of an equilateral triangle circumscribed in a circle of radius R, is given by,

2Rsin(60)

Area of the equilateral triangle = (3/4)side2

= (3/4)(4x32x32x3/4)

= 1330.17 cm2

Area of circle = 3.14x32x32 = 3215.36 cm2

Area of design = Area of circle - Area of triangle = 3215.36 - 1330.17 = 1885.2 cm2

Regards,

Team,

TopperLearning.

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