NEET Class neet Answered
To code 50 amino acids in a polypeptide chain, what will be the minimum number of nucleotides in the cistron? (1)50,(2)153,(3)306,(4)300
Asked by patra04011965 | 09 Feb, 2019, 10:38: AM
Expert Answer
Cistron is a double stranded DNA segment which codes polypeptides.
For coding 50 amino acids 51 codons are needed (50 codons + 1 stop codon)
Each codon is triplet. And triplet have 3 nitrogen bases.
So number of nucleotide for 51 codons =51*3=153
So total number of nucleotides will 153 *2 =306(Cistron is a double stranded DNA segment which codes polypeptides. So adding nucleotides of both the strands)
Answer is (3)
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