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the volume of 0.5 molars NaOH solution required for complete neutralization of 3.65 gram HCl is  
Asked by kushagra28feb | 13 Jun, 2019, 10:09: PM
answered-by-expert Expert Answer
Given:
 
Molarity of NaOH = 0.5 M
 
Mass of HCl = 3.65 gm
 
The neutralisation reaction is given as,
 
HCl space space space space space plus space space NaOH space space space rightwards arrow with blank on top space space NaCl space space space plus space straight H subscript 2 straight O 1 space mol space space space space space space space 1 space mol space space space space space space space space space space space 1 space mol space space space space space space 1 space mol space space space space space straight n subscript 1 space space space space space space space space space space space space space space space space straight n subscript 2 end subscript That space is space straight n subscript 1 space moles space of space HCl space requires space straight n subscript 2 space end subscript space moles space of space NaOH space for space complete space neutralisation. straight n subscript 1 space equals space straight n subscript 2 space space.... left parenthesis 1 right parenthesis We space have comma Molarity space equals space fraction numerator No. space of space moles over denominator Vol. space in space straight L end fraction therefore space No. space of space moles space equals space space Molarity space cross times Vol. space in space straight L space space space space space space space space space space space space space space space space space space space space straight n subscript 2 space space equals space 0.5 cross times straight V Now comma straight n subscript 1 space equals space fraction numerator Weight space over denominator Moleculat space wt end fraction space space space space space equals fraction numerator 3.65 over denominator 36.5 end fraction space straight n subscript 1 space equals 0.1 space mole Putting space values space in space eq left parenthesis 1 right parenthesis 0.5 cross times straight V space equals 0.1 space space space space space space space space space space straight V space equals fraction numerator 0.1 over denominator 0.5 end fraction space space space space space space space space space space straight V space equals space 0.2 space straight L space space space space space space space space space space space space space space equals space 200 space ml space
 
Volume of NaOH solution required for complete neutralization of 3.65 gram HCl is 200 ml.
Answered by Varsha | 14 Jun, 2019, 11:14: AM

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