Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

the volume of 0.5 molars NaOH solution required for complete neutralization of 3.65 gram HCl is

 

Asked by kushagra28feb 13th June 2019, 10:09 PM
Answered by Expert
Answer:
Given:
 
Molarity of NaOH = 0.5 M
 
Mass of HCl = 3.65 gm
 
The neutralisation reaction is given as,
 
HCl space space space space space plus space space NaOH space space space rightwards arrow with blank on top space space NaCl space space space plus space straight H subscript 2 straight O
1 space mol space space space space space space space 1 space mol space space space space space space space space space space space 1 space mol space space space space space space 1 space mol
space space space space space straight n subscript 1 space space space space space space space space space space space space space space space space straight n subscript 2 end subscript

That space is space straight n subscript 1 space moles space of space HCl space requires space straight n subscript 2 space end subscript space moles space of space NaOH space for space complete space neutralisation.


straight n subscript 1 space equals space straight n subscript 2 space space.... left parenthesis 1 right parenthesis

We space have comma

Molarity space equals space fraction numerator No. space of space moles over denominator Vol. space in space straight L end fraction

therefore space No. space of space moles space equals space space Molarity space cross times Vol. space in space straight L

space space space space space space space space space space space space space space space space space space space space straight n subscript 2 space space equals space 0.5 cross times straight V
Now comma

straight n subscript 1 space equals space fraction numerator Weight space over denominator Moleculat space wt end fraction

space space space space space equals fraction numerator 3.65 over denominator 36.5 end fraction

space straight n subscript 1 space equals 0.1 space mole

Putting space values space in space eq left parenthesis 1 right parenthesis

0.5 cross times straight V space equals 0.1

space space space space space space space space space space straight V space equals fraction numerator 0.1 over denominator 0.5 end fraction

space space space space space space space space space space straight V space equals space 0.2 space straight L

space space space space space space space space space space space space space space equals space 200 space ml space
 
Volume of NaOH solution required for complete neutralization of 3.65 gram HCl is 200 ml.
Answered by Expert 14th June 2019, 11:14 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer 10/10

Your answer has been posted successfully!

Chat with us on WhatsApp