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ICSE Class 9 Answered

The parallel sides of a trapezium are 30 cm and 10 cm and the other two sides two sides are 13 cm and 21 cm. Find its area.
Asked by Topperlearning User | 29 Aug, 2017, 12:33: PM
answered-by-expert Expert Answer




begin mathsize 12px style Draw space BP parallel to AD space so space as space to space complete space parallelogram space ABPD BP equals AD equals 13 space cm DP equals AB equals 10 space cm PC equals DC minus DP equals 30 minus 10 equals 20 space cm In space increment BPC straight S equals fraction numerator straight a plus straight b plus straight c over denominator 2 end fraction equals fraction numerator 21 plus 13 plus 20 over denominator 2 end fraction equals 27 space cm Area space of space increment BPC equals In space increment ABD comma straight S equals fraction numerator straight a plus straight b plus straight c over denominator 2 end fraction equals fraction numerator 6 plus 4 plus 8 over denominator 2 end fraction equals 9 space cm Area space of space increment ABD equals square root of straight S open parentheses straight S minus straight a close parentheses open parentheses straight S minus straight b close parentheses left parenthesis straight S minus straight c right parenthesis end root equals square root of 27 open parentheses 27 minus 21 close parentheses open parentheses 27 minus 13 close parentheses open parentheses 27 minus 20 close parentheses end root equals square root of 15876 equals 126 space sq. space cm 1 half cross times base cross times altitude equals 1 half PC cross times straight h 126 equals 1 half cross times 20 cross times straight h straight h equals 12.6 space cm Area space of space trapezium space ABCD equals 1 half open parentheses 10 plus 30 close parentheses cross times 12.6 equals 252 space sq. space cm end style

Answered by | 29 Aug, 2017, 02:33: PM

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