The altitude of a right triangle is twice the base. If the area is 36 m2, what are the dimensions of this triangle?
Here, let us assume the base of the triangle be b.
Given that ,
Altitude (h) = 2 x base (b) = 2b
Also, area of the triangle = 36 m2
Substituting the known values in the formula for area:
Area = x b x h
36 = x b x 2b
b2 = 36 = 62
or b = 6
Thus, the base of the triangle = 6 m
And, the height of the triangle = 2 x 6 = 12 m
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