NEET Class neet Answered
Parents: FFPP X FFPP
Let us assume the genotype of the birds to be as stated below-
Cock A – FFPP
Cock B – FfPp
Hen C – FfPP
Hen D – FFPp
We will now carry out the crosses as mentioned in the question to verify their possible genotypes.
Cock A was crossed with Hen C.
So, FFPP X FfPP
Gametes – FP, FP, fP
Offspring – FFPP, FfPP
Cock A was crossed with Hen D.
So, FFPP X FFPp
Gametes – FP, Fp
Offspring – FFPp
So, this matches our given data that when cock A is crossed with hen C and hen D, it produces chicks which are feathered and pea combed.
Cock B was crossed with Hen C.
So, FfPp X FfPP
Gametes – FP, fP, Fp, fp
Offspring – FFPP, FfPp, FfPp, ffPp
So, this matches our given data that when cock B is crossed with hen C, it produces chicks which are both feathered and cleaned but only pea combed.
Cock B was crossed with Hen D.
So, FfPp X FFPp
Gametes – FP, fP, Fp, fp
Offspring – FfPP, FFPP, Ffpp
So, this matches our given data that when cock B is crossed with hen D, it produces chicks which are all feathered but part pea combed and part single combed.
Therefore, the genotypes of the cocks and hens are as follows-
Cock A – FFPP
Cock B – FfPp
Hen C – FfPP
Hen D – FFPp