NEET Class neet Answered

         Parents: FFPP X FFPP

Let us assume the genotype of the birds to be as stated below-

Cock A – FFPP

Cock B – FfPp

Hen C – FfPP

Hen D – FFPp

We will now carry out the crosses as mentioned in the question to verify their possible genotypes.

Cock A was crossed with Hen C.

So, FFPP X FfPP

Gametes – FP, FP, fP

Offspring – FFPP, FfPP

Cock A was crossed with Hen D.

So, FFPP X FFPp

Gametes – FP, Fp

Offspring – FFPp

So, this matches our given data that when cock A is crossed with hen C and hen D, it produces chicks which are feathered and pea combed.

Cock B was crossed with Hen C.

So, FfPp X FfPP

Gametes – FP, fP, Fp, fp

Offspring – FFPP, FfPp, FfPp, ffPp

So, this matches our given data that when cock B is crossed with hen C, it produces chicks which are both feathered and cleaned but only pea combed.

Cock B was crossed with Hen D.

So, FfPp X FFPp

Gametes – FP, fP, Fp, fp

Offspring – FfPP, FFPP, Ffpp

         So, this matches our given data that when cock B is crossed with hen D, it produces chicks which are all feathered but part pea combed and part single combed.

Therefore, the genotypes of the cocks and hens are as follows-

Cock A – FFPP

Cock B – FfPp

Hen C – FfPP

Hen D – FFPp