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Solve the question in photo showing each step clearly...
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Asked by Vidushi412 | 06 Apr, 2019, 09:51: PM
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begin mathsize 12px style S space equals space fraction numerator x over denominator 1 space minus space x squared end fraction space plus space fraction numerator x squared over denominator 1 space minus space x to the power of 4 end fraction space plus space fraction numerator x to the power of 4 over denominator 1 minus x to the power of 8 end fraction space plus space................... space t o space infinity S space equals space x open parentheses 1 space minus x squared close parentheses to the power of negative 1 end exponent space plus space x squared open parentheses 1 minus x to the power of 4 close parentheses to the power of negative 1 end exponent space plus x to the power of 4 open parentheses 1 space minus space x to the power of 8 close parentheses to the power of negative 1 end exponent space plus................ space t o space infinity S space equals space x left parenthesis 1 plus x squared plus x to the power of 4 plus x to the power of 6 plus.......... right parenthesis space plus space x squared left parenthesis 1 plus x to the power of 4 plus x to the power of 8 plus x to the power of 12 plus......... right parenthesis space plus x to the power of 4 left parenthesis 1 plus x to the power of 8 plus x to the power of 16 plus....... right parenthesis plus....... t o space infinity S space equals space space x left parenthesis 1 plus x squared plus x to the power of 4 plus x to the power of 6 plus.......... right parenthesis space plus space x left parenthesis x plus x to the power of 5 plus x to the power of 9 plus x to the power of 13 plus......... right parenthesis space plus x left parenthesis x cubed plus x to the power of 11 plus x to the power of 19 plus....... right parenthesis plus....... t o space infinity S space equals space space x left parenthesis 1 plus x plus x squared plus x cubed plus x to the power of 4 plus x to the power of 5 plus x to the power of 6 plus......... space space space t o space infinity right parenthesis space equals space x left parenthesis 1 minus x right parenthesis to the power of negative 1 end exponent space equals space fraction numerator x over denominator 1 space minus space x end fraction end style
Answered by Renu Varma | 07 Apr, 2019, 12:43: PM

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